Question:medium

The electric field strength at a point in an electric field is 30 N/C. Find the force experienced by a charge of 20 C at that point.

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The force on a charge in an electric field is directly proportional to the electric field strength and the charge.
Updated On: Jan 15, 2026
  • 600 N
  • 30 N
  • 20 N
  • 300 N
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The Correct Option is A

Solution and Explanation

The force on a charge in an electric field is: \[ F = E \times q \] Given: - \( E = 30 \, \text{N/C} \) - \( q = 20 \, \text{C} \) Calculate: \[ F = 30 \times 20 = 600 \, \text{N} \] The force is 600 N.
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