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The electric field strength at a point in an electric field is 30 N/C. Find the force experienced by a charge of 20 C at that point.
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The force on a charge in an electric field is directly proportional to the electric field strength and the charge.
JEECUP - 2024
JEECUP
Updated On:
Jan 15, 2026
600 N
30 N
20 N
300 N
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The Correct Option is
A
Solution and Explanation
The force on a charge in an electric field is: \[ F = E \times q \] Given: - \( E = 30 \, \text{N/C} \) - \( q = 20 \, \text{C} \) Calculate: \[ F = 30 \times 20 = 600 \, \text{N} \] The force is 600 N.
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