Question:medium

The distance between the internal and external centres of similitude with respect to the circles \[ x^2+y^2+4x+6y+12=0 \] and \[ x^2+y^2-6x-4y+9=0 \] is:

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For two circles with radii \(r_1\) and \(r_2\) and centre distance \(d\), remember the shortcut \[ \text{Distance between internal and external centres of similitude} = \frac{2r_1r_2d}{|r_1^2-r_2^2|}. \] This avoids finding the centres of similitude individually.
Updated On: Jun 17, 2026
  • \(5\sqrt{2}\)
  • \(\dfrac{20\sqrt{2}}{3}\)
  • \(16\)
  • \(5\)
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The Correct Option is B

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