To determine the new duration of a year when the distance between the Sun and Earth increases to \(3R\), we need to apply Kepler's Third Law of Planetary Motion. This law states:
T^2 \propto R^3
Where \( T \) is the orbital period (duration of a year) and \( R \) is the average distance from the Sun.
Given: \( R_{\text{initial}} = R \) and \( T_{\text{initial}} = 1 \text{ year} \). At this distance, the Earth's orbital period is 1 year.
If the new distance \( R_{\text{new}} = 3R \), we need to find \( T_{\text{new}} \).
According to Kepler's Third Law:
\frac{T_{\text{new}}^2}{T_{\text{initial}}^2} = \frac{R_{\text{new}}^3}{R_{\text{initial}}^3}
\frac{T_{\text{new}}^2}{1^2} = \frac{(3R)^3}{(R)^3}
Simplifying the right side, we get:
\frac{T_{\text{new}}^2}{1} = \frac{27R^3}{R^3} = 27
Thus, T_{\text{new}}^2 = 27
Taking the square root on both sides:
T_{\text{new}} = \sqrt{27} = 3\sqrt{3} \text{ years}
Therefore, the duration of the year when the distance between the Sun and Earth becomes \(3R\) is 3\(\sqrt{3}\) years.
This confirms that the correct answer is: 3 \(\sqrt{3}\) years.

A person moved from A to B on a circular path as shown in figure If the distance travelled by him is 60 m, then the magnitude of displacement would be Given ( Cos 135° = -0.7)