Question:medium

The dimensions of a triangle are 15 cm, 8 cm and 17 cm. What is the area of a circle having radius (r + 4) cm if 'r' is the inradius of the given triangle?

Updated On: Jan 13, 2026
  • 36π cm2
  • 49π cm2
  • 54π cm2
  • 64π cm2
  • 81π cm2
Show Solution

The Correct Option is B

Solution and Explanation

The correct answer is option (B):
49π cm2

Let's break this problem down step by step. We need to find the area of a circle, and we know its radius is related to the inradius of a given triangle.

First, let's check if the triangle is a right-angled triangle. We can use the Pythagorean theorem: a² + b² = c², where c is the longest side (the hypotenuse).

In this case, the sides are 15 cm, 8 cm, and 17 cm.
8² + 15² = 64 + 225 = 289
17² = 289

Since 8² + 15² = 17², the triangle is a right-angled triangle.

Now, we need to find the inradius (r) of the triangle. For a right-angled triangle, the inradius can be calculated using the formula: r = (a + b - c) / 2, where a and b are the legs and c is the hypotenuse.

So, r = (8 + 15 - 17) / 2 = (23 - 17) / 2 = 6 / 2 = 3 cm.

The radius of the circle is given as (r + 4) cm. Since r = 3 cm, the circle's radius is (3 + 4) = 7 cm.

The area of a circle is calculated using the formula: Area = π * radius²

Therefore, the area of the circle is π * 7² = 49π cm².

The correct answer is 49π cm².
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