Question:medium

The differential equation representing the family of parabolas having vertex at the origin and axis along the positive Y-axis is

Show Hint

Eliminate the arbitrary constant 'a' to find the differential equation.
Updated On: Jun 19, 2026
  • $x\frac{dy}{dx}-2y=0$
  • $\frac{dy}{dx}+xy=0$
  • $x\frac{dy}{dx}+y=0$
  • $x^{2}\frac{dy}{dx}+y=0$
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
Derive the differential equation by eliminating the arbitrary constant from the family's general equation.

Step 2: Key Formula or Approach:

Family of parabolas with vertex $(0,0)$ and axis along positive Y-axis: $x^2 = 4ay$.

Step 3: Detailed Explanation:

Equation: $x^2 = 4ay$ -----(1)
Differentiate both sides with respect to $x$: \[ 2x = 4a \frac{dy}{dx} \] -----(2)
From (1), we have $4a = \frac{x^2}{y}$.
Substitute this into (2): \[ 2x = \frac{x^2}{y} \frac{dy}{dx} \] Multiply by $\frac{y}{x}$ (assuming $x \neq 0$): \[ 2y = x \frac{dy}{dx} \] \[ x \frac{dy}{dx} - 2y = 0 \]

Step 4: Final Answer:

The differential equation is $x \frac{dy}{dx} - 2y = 0$.
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