Question:hard

The difference between the maximum and minimum values of the objective function \(Z = 3x+5y\), subject to the constraints \(x+3y\leq 60\), \(x+y\geq 10\), \(x-y\leq 0\), \(x,y\geq 0\) is

Show Hint

Find the corner points of the feasible region and evaluate Z at each.
Updated On: Oct 1, 2026
  • \(50\)
  • \(60\)
  • \(70\)
  • \(80\)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Region
The region is bounded by $x \geq 0$, $y \geq x$, $x + y \geq 10$ and $x + 3y \leq 60$.

Step 2: Vertices
$(0,10)$, $(5,5)$, $(15,15)$, $(0,20)$.

Step 3: Values
$Z = 50, 40, 120, 100$ respectively. Max $-$ min $= 120 - 40 = 80$. Option (D).

Final Answer:
Option (D). \[ \boxed{80} \]
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