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The current amplification factor of a transistor in common emitter configuration is 80. If the emitter current is 2.43 mA, then the base current is
The current amplification factor of a transistor in common emitter configuration is 80. If the emitter current is 2.43 mA, then the base current is
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In transistor circuits, the relationship between currents is $I_E = I_C + I_B$. In the Common Emitter (CE) configuration, the current gain is $\beta = I_C/I_B$. These relations are combined to give $I_E = (\beta+1)I_B$, which is often the quickest way to solve for the base current.
Updated On: Mar 30, 2026
- 15 $\mu$A
- 1.5 $\mu$A
- 3 $\mu$A
- 30 $\mu$A
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The Correct Option is D
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