Question

The correct truth table for the following logic circuit is :

• A.
• B.
• C.
• D.

Answer 1

The Correct Option is B

The circuit comprises an AND gate, a NOT gate, and an OR gate. The output \(Y\) is calculated as follows:

1. The AND gate's output is \(A \cdot B\).
2. The NOT gate's output is \(\overline{A \cdot B}\).
3. The final output \(Y\) is the OR operation between \(\overline{A \cdot B}\) and \(B\):

\[ Y = \overline{A \cdot B} + B \]

Step-by-Step Truth Table Evaluation:

A	B	A · B	\(\overline{A \cdot B}\)	Y = \(\overline{A \cdot B}\) + B
0	0	0	1	1
0	1	0	1	1
1	0	0	1	1
1	1	1	0	1

Therefore, the accurate truth table is presented in Option (2).