Question

The correct IUPAC name of K₂MnO₄ is

• A. Potassium tetraoxopermanganate (VI)
• B. Potassium tetraoxidomanganate (VI)
• C. Dipotassium tetraoxidomanganate (VII)
• D. Potassium tetraoxidomanganese (VI)

Answer 1

The Correct Option is B

To determine the IUPAC name for K₂MnO₄, we must identify the oxidation state of manganese and apply IUPAC naming conventions.

1. First, determine manganese's oxidation state in K₂MnO₄. Potassium (K) typically has a +1 oxidation state.
2. Two potassium atoms contribute a total charge of +2.
3. Oxygen generally has a -2 oxidation state. Four oxygen atoms contribute a total charge of -8.
4. K₂MnO₄ is a neutral compound, so the sum of oxidation states is zero. Let the oxidation state of manganese (Mn) be x.
5. The equation is: \(2(+1) + x + 4(-2) = 0\).
6. This simplifies to: \(2 + x - 8 = 0\).
7. Solving for x yields: \(x = +6\).
8. Manganese is in the +6 oxidation state.
9. According to IUPAC nomenclature, the anion is named using the element's root followed by the suffix '-ate', with the oxidation state indicated by Roman numerals in parentheses.
10. Therefore, the anion MnO₄²⁻ is named 'tetraoxidomanganate(VI)', where 'tetra' denotes four oxygens and the oxidation state of manganese is +6.

The complete IUPAC name for K₂MnO₄ is:

Potassium tetraoxidomanganate (VI).

This name is correct, while other options are incorrect due to errors in oxidation state or prefixes. The accurate designation is "Potassium tetraoxidomanganate (VI)".