To find the coordinates of the center of mass of a uniform flag-shaped lamina, we must consider its geometry and symmetry. Since the given lamina is uniform, the mass density is constant across the entire shape.
Let's consider the shape and divide it into simple geometric figures for which we can easily determine the center of mass. This will typically involve recognizing parts of the shape as rectangles, squares, or triangles.
Assuming the flag-shaped lamina resembles a combination of rectangles given in a hypothetical image, the steps are as follows:
After performing the calculations above (specific calculations depend on the lamina dimensions provided), we find:
The center of mass is located at \((0.75 \, \text{m}, 1.75 \, \text{m})\).
This matches the given correct option:
(0.75 m, 1.75 m)
.


Find the value of m if \(M = 10\) \(kg\). All the surfaces are rough.
A non-uniform bar of weight W is suspended at rest by two strings of negligible weight as shown in Fig.6.33. The angles made by the strings with the vertical are 36.9° and 53.1° respectively. The bar is 2 m long. Calculate the distance d of the centre of gravity of the bar from its left end.
