Question:medium
The conductivity of a saturated solution of BaSO₄ is 3.06 × 10⁻⁶ Ω⁻¹cm⁻¹ and its equivalent conductance is 1.53 Ω⁻¹cm²eq⁻¹. The Kₛp for BaSO₄ is:
The conductivity of a saturated solution of BaSO₄ is 3.06 × 10⁻⁶ Ω⁻¹cm⁻¹ and its equivalent conductance is 1.53 Ω⁻¹cm²eq⁻¹. The Kₛp for BaSO₄ is:
Show Hint
Conductivity data can be used to find solubility.
Updated On: Mar 17, 2026
- 4 × 10⁻¹²
- 2.5 × 10⁻⁹
- 2.5 × 10⁻¹³
- 4 × 10⁻⁶
Show Solution
The Correct Option is A
Solution and Explanation
Was this answer helpful?
0
Top Questions on reaction mechanism
- Given below are two statements:
Statement I: Phenol on treatment with \( \mathrm{CHCl_3/aq.\ KOH} \) under refluxing condition, followed by acidification produces p-hydroxy benzaldehyde as the major product and o-hydroxy benzaldehyde as the minor product.
Statement II: The mixture of p-hydroxybenzaldehyde and o-hydroxybenzaldehyde can be easily separated through steam distillation.
In the light of the above statements, choose the correct answer from the options given below- JEE Main - 2026
- Chemistry
- reaction mechanism
- Given below are two statements:
Statement I: The dipole moment of R–CN is greater than R–NC and R–NC can undergo hydrolysis under acidic medium to produce R–COOH.
Statement II: R–CN hydrolyses under acidic medium to produce a compound which on treatment with SOCl$_2$, followed by the addition of NH$_3$ gives another compound (X). This compound (X) on treatment with NaOCl/NaOH gives a product, that on treatment with CHCl$_3$/KOH/$\Delta$ produces R–NC.
In the light of the above statements, choose the correct answer from the options given below.
- JEE Main - 2026
- Chemistry
- reaction mechanism
The correct order of the rate of reaction of the following reactants with nucleophile by \( \mathrm{S_N1} \) mechanism is:
(Given: Structures I and II are rigid)
- JEE Main - 2026
- Chemistry
- reaction mechanism
- Which reagent gives bright red ppt. With \(Ni^{2+}\) in basic medium?
- JEE Main - 2024
- Chemistry
- reaction mechanism
- Want to practice more? Try solving extra ecology questions todayView All Questions