Question:medium

The complex numbers $z$ satisfying $\left|\dfrac{i+z}{i-z}\right| = 1$ lie on

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$|z - a| = |z - b|$ is the perpendicular bisector of the segment joining $a$ and $b$ in the complex plane. Here $a = -i$ and $b = i$, so bisector is the real axis ($x$-axis).
Updated On: Apr 8, 2026
  • the circle $x^{2} + y^{2} = 1$
  • the $x$-axis
  • the $y$-axis
  • the line $x + y = 1$
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The Correct Option is B

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