Question:medium

The approximate value of \(\int_1^5 x^2 dx\) using trapezoidal rule with \(n = 4\) is

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Exact value of \(\int_1^5 x^2 dx = [x^3/3]_1^5 = (125 - 1)/3 = 124/3 \approx 41.33\).
Updated On: Apr 7, 2026
  • 41
  • 41.5
  • 41.75
  • 42
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The Correct Option is D

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