Question:medium

The angle of a prism is 60\(^\circ\) and its refractive index is \(\sqrt{2}\). The angle of minimum deviation suffered by a ray of light in passing through it is

Show Hint

For minimum deviation in a prism: \(n = \dfrac{\sin\frac{A+D_m}{2}}{\sin\frac{A}{2}}\). Rearrange to find \(D_m\).
Updated On: Apr 8, 2026
  • about 20\(^\circ\)
  • 30\(^\circ\)
  • 60\(^\circ\)
  • 45\(^\circ\)
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0


Questions Asked in MET exam