Question:medium

The amplitude of the electric field associated with a light beam of intensity $\frac{15}{\pi}$ Wm$^{-2}$ is

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The formula for the intensity of an EM wave is $I = \frac{1}{2}\epsilon_0 c E_0^2$. For easier calculation, it's often helpful to use the relation $\epsilon_0 c = \frac{1}{4\pi k c} \cdot c = \frac{1}{4\pi k}$ where $k=9\times 10^9$, or to substitute for $\epsilon_0$ from $k = 1/(4\pi\epsilon_0)$.

Updated On: Mar 30, 2026

120 NC$^{-1}$
15 NC$^{-1}$
60 NC$^{-1}$
30 NC$^{-1}$

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The Correct Option is C

Solution and Explanation

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