Question:medium

Sunlight is reflected from a material. The reflected light is 100% polarized at a certain instant. Assuming refractive index of material equal to 1.732, the angle between the sun and the horizon at that instant is

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Always be careful about which angle is being asked for in problems involving reflection and refraction. The laws use the angle with the normal, but questions might ask for the angle with the surface (glancing/grazing angle) or the angle of deviation. Drawing a simple diagram of the incident ray, the surface, and the normal can prevent confusion.
Updated On: Feb 20, 2026
  • 30°
  • 45°
  • 60°

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The Correct Option is A

Solution and Explanation

Step 1: Conceptual Foundation: When unpolarized light reflects off a dielectric surface at the polarizing angle (Brewster's angle, \(\theta_p\)), the reflected light becomes completely plane-polarized. Brewster's Law establishes a relationship between this angle and the material's refractive index. The problem requires determining the sun's angle with the horizon, which is complementary to the angle of incidence.
Step 2: Essential Formulae/Methodology: 1. Brewster's Law: \( n = \tan(\theta_p) \), where \(n\) denotes the refractive index and \(\theta_p\) is the polarizing angle of incidence. 2. The angle of incidence (\(\theta_p\)) is measured relative to the normal (perpendicular) to the surface. The angle of the sun with the horizon (\(\alpha\)) is measured relative to the horizontal surface itself. These two angles are complementary: \( \theta_p + \alpha = 90^\circ \).
Step 3: Detailed Calculation: 1. Brewster's Angle Calculation (\(\theta_p\)): Given the refractive index \( n = 1.732 \). It is noted that \( 1.732 \approx \sqrt{3} \). Applying Brewster's Law: \[ \tan(\theta_p) = n = \sqrt{3} \] The angle whose tangent is \(\sqrt{3}\) is \(60^\circ\). \[ \theta_p = 60^\circ \] 2. Angle with Horizon Calculation (\(\alpha\)): The angle of incidence (\(\theta_p\)) is the angle between the incident sunlight and the normal to the horizon. The angle between the sun and the horizon (\(\alpha\)) is the angle between the sunlight and the horizontal surface. Geometrically, \( \alpha = 90^\circ - \theta_p \). \[ \alpha = 90^\circ - 60^\circ = 30^\circ \] Step 4: Concluding Result: The angle between the sun and the horizon is 30°.
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