The oxidation state of bromine in its oxoacids increases as the number of oxygen atoms increases.
To determine the sum of the oxidation states of bromine in bromic acid (HBrO3) and perbromic acid (HBrO4), we need to calculate each one separately:
Step 1: Oxidation state in bromic acid (HBrO3)
In HBrO3, assume the oxidation state of bromine (Br) is x.
The oxidation state of hydrogen (H) is +1, and the oxidation state of oxygen (O) is -2. The sum of oxidation states in a neutral compound is 0.
Setting up the equation based on HBrO3:
1(x) + 1(+1) + 3(-2) = 0 → x + 1 - 6 = 0 → x - 5 = 0 → x = +5
Step 2: Oxidation state in perbromic acid (HBrO4)
In HBrO4, assume the oxidation state of bromine (Br) is y.
The compound is also neutral, so the sum of oxidation states equals 0.
Setting up the equation based on HBrO4:
1(y) + 1(+1) + 4(-2) = 0 → y + 1 - 8 = 0 → y - 7 = 0 → y = +7
Step 3: Sum of oxidation states
The sum of oxidation states of bromine in both acids is: +5 (HBrO3) + +7 (HBrO4) = 12
Conclusion: The sum of oxidation states of bromine in bromic acid and perbromic acid is 12. This value is confirmed to be within the given range of 12,12.