Question:medium
Sum of oxidation state (magnitude) and coordination number of cobalt in \(Na[Co(bpy)Cl_4]\) is____ .
(Given : bpy =
)
Sum of oxidation state (magnitude) and coordination number of cobalt in \(Na[Co(bpy)Cl_4]\) is____ .
(Given : bpy =)
(Given : bpy =
)Updated On: Mar 13, 2026
Show Solution
Correct Answer: 9
Solution and Explanation
To determine the sum of the oxidation state magnitude and coordination number of cobalt in the compound \(Na[Co(bpy)Cl_4]\), follow these steps:
- Identify the components: The complex is composed of a cobalt ion, bipyridine (bpy), and four chloride ions.
- Oxidation state calculation: Assume cobalt's oxidation state is \(x\). The oxidation state of chloride (Cl) is \(-1\). The bipyridine (bpy) is a neutral ligand.
- The complex ion can be represented as \([Co(bpy)Cl_4]^-\).
- Charge balance equation: \(x + 0 + 4(-1) = -1\) (charge of entire complex ion).
- Simplify to find \(x\): \(x - 4 = -1 \rightarrow x = +3\).
- Therefore, cobalt's oxidation state is \(+3\).
- Coordination number: Cobalt is coordinated to bipyridine (bidentate, counts as 2) and four chloride ions.
- Total coordination number = 2 (from bpy) + 4 (from chloride) = 6.
- Sum of oxidation state magnitude and coordination number:
- Oxidation state magnitude = \(|+3| = 3\).
- Sum = 3 (magnitude) + 6 (coordination number) = 9.
The computed value, \(9\), falls within the expected range of \(9,9\).
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