Question:medium

\(\sum_{k=0}^{10} {}^{20}C_k\) is equal to

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Use \(\sum_{k=0}^n \binom{n}{k} = 2^n\) and symmetry \(\binom{n}{k} = \binom{n}{n-k}\).
Updated On: Apr 23, 2026
  • \(2^{19} + \frac{1}{2} {}^{20}C_{10}\)
  • \(2^{19}\)
  • \({}^{20}C_{10}\)
  • None of these
Show Solution

The Correct Option is A

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