To solve this question, we need to evaluate the truthfulness of two given statements about the time period of a simple pendulum.
Statement-1 claims: "Time period of simple pendulum is increased if density of material of pendulum is increased."
In the theory of simple pendulums, the time period T is not dependent on the mass or the density of the pendulum bob. The formula for the period of a simple pendulum is:
T = 2 \pi \sqrt{\frac{l}{g}}From this formula, it is clear that the time period T depends only on l (the length of the pendulum) and g (the acceleration due to gravity), but not on the density of the material of the pendulum.
Therefore, Statement 1 is false.
Statement-2 claims: "Time period of simple pendulum is T = 2 \pi \sqrt{\frac{l}{g}}."
This is the standard formula for the time period of a simple pendulum, assuming small angle oscillations. Therefore, Statement 2 is true.
Based on the analysis above:
The correct answer is: Statement I is false; Statement II is true.
Assuming in forward bias condition there is a voltage drop of \(0.7\) V across a silicon diode, the current through diode \(D_1\) in the circuit shown is ________ mA. (Assume all diodes in the given circuit are identical) 

