Question:medium

$(\sqrt{3}+i)^{10} + (\sqrt{3}-i)^{10} =$

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For expressions of the form $(x+iy)^n + (x-iy)^n$, using De Moivre's theorem is the most efficient method. Remember that the sum will be $2r^n\cos(n\theta)$ and the difference will be $2ir^n\sin(n\theta)$.
Updated On: Mar 30, 2026
  • $1024\sqrt{3}$
  • 1024
  • 2048
  • $512\sqrt{3}$
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The Correct Option is B

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