Step 1: Identify the acid in vinegar.
Vinegar's sour taste comes from acetic acid, $CH_3COOH$. This is a carbon based acid that does not break apart completely in water, so we call it a weak acid.
Step 2: Identify the base used to make its sodium salt.
To convert an acid into its sodium salt, we always react it with a sodium base, here sodium hydroxide, $NaOH$. $NaOH$ dissolves completely in water and ionises fully, so it counts as a strong base. \[ CH_3COOH + NaOH \to CH_3COONa + H_2O \]
Step 3: Combine the two strengths.
One partner is weak, the acid, the other is strong, the base, so the resulting salt, sodium acetate, falls in the weak acid plus strong base category. A quick check, a solution of this salt turns slightly basic, pH above 7, on hydrolysis, which is the signature behaviour of this exact salt type.
Step 4: Conclude.
Sodium acetate, the sodium salt of vinegar's acid, is a salt of weak acid and strong base. \[ \boxed{\text{Salt of weak acid + strong base}} \]