Question:medium

Find the correct statement from following :

Show Hint

In series: Voltages add up, resistance adds up, current remains same.
In parallel: Currents add up, reciprocal of resistances add up, voltage remains same.
  • The equivalent resistance of several resistances in series is equal to the sum of their individual resistances.
  • The equivalent resistance of several resistances in parallel is equal to the sum of their individual resistances.
  • In series circuit, total current is equal to sum of the separate currents through each branch of combination.
  • In parallel circuit, the total current is equal to sum of the separate currents through each branch of combination.
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Recall the two basic rules.
For series resistors, \[ R_{eq} = R_1 + R_2 + \dots \] and the current stays the same everywhere. For parallel resistors, \[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots \] and it is the current that splits up among the branches.
Step 2: Test option A.
Option A says the series equivalent resistance is the sum of the individual resistances, which is exactly the series rule above, so this statement is true and worded precisely as the textbook law.
Step 3: Rule out the rest quickly.
Option B wrongly applies the series addition rule to a parallel circuit. Option C wrongly claims current adds up in series, when really it stays constant throughout a series loop. Since option A is the one statement that matches a standard law of combination word for word, it is the answer being asked for.
\[ \boxed{R_{eq} = R_1 + R_2 + \dots + R_n \text{ for a series combination}} \]
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