Step 1: Draw the nodes.
In a parallel network the two resistors have their left ends tied together and their right ends tied together, and these two junction points are the battery terminals. Voltage is a property of the junction pair, so whatever appears across one branch appears across the other.
Step 2: Fix the common voltage.
That common voltage is simply the battery e.m.f. \(V\). Hence \(V_{10} = V_{15} = V\); the drops are identical, confirming statement (iv) and killing statement (iii).
Step 3: Compare branch currents with Ohm's law.
Current in a branch is \(I = V/R\). The smaller resistance carries the bigger current, so \(I_{10} = V/10\) exceeds \(I_{15} = V/15\). Thus the \(10\,\Omega\) current is greater (statement (i) claims the opposite, so it is false), and the currents are unequal (statement (ii) is false).
Step 4: Select.
Only the equal-potential-drop statement survives.
\[\boxed{\text{Same potential drop across both}}\]