Question:medium

Refer to the figure given below. The values of $I_1, I_2$ and $I_3$ are ______}

Updated On: Jun 6, 2026
  • $I_1 = 2.5 \text{ A}, I_2 = 1.875 \text{ A}, I_3 = 1.875 \text{ A}$
  • $I_1 = 1.875 \text{ A}, I_2 = 2.5 \text{ A}, I_3 = 1.875 \text{ A}$
  • $I_1 = 1.875 \text{ A}, I_2 = 1.875 \text{ A}, I_3 = 2.5 \text{ A}$
  • $I_1 = 2.5 \text{ A}, I_2 = 2.5 \text{ A}, I_3 = 1.875 \text{ A}$
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
The topic of this question is Current Electricity, specifically circuit analysis.
We need to find the specific currents $I_1, I_2, I_3$ in a complex bridge network that contains multiple voltage sources and resistors.
Step 2: Key Formula or Approach:
Kirchhoff's Current Law (KCL) is applied at the junction nodes.
The sum of currents leaving a node equals zero: $\sum \frac{V_{node} - V_{adjacent}}{R} = 0$.
Step 3: Detailed Explanation:
By defining appropriate nodes and setting a reference potential of $0$V at the bottom-most junction, we can set up nodal equations.
Due to the symmetry of the circuit elements and voltage sources, standard linear equations can be formed.
Solving the KCL equations for the top and central nodes yields the specific branch potentials.
Using Ohm's law with these potentials gives the currents:
$I_1 = 1.875 \text{ A}$.
$I_2 = 2.5 \text{ A}$.
$I_3 = 1.875 \text{ A}$.
Step 4: Final Answer:
The currents are $I_1 = 1.875 \text{ A}, I_2 = 2.5 \text{ A}, I_3 = 1.875 \text{ A}$.
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