Question

Which of the following is wrong?

• A. A will be to the immediate right of C
• B. D will be to the immediate left of B
• C. E will be to the immediate right of A
• D. F will be to the immediate left of D
• A. B will be to the immediate left of D
• B. H will be to the immediate right of A
• C. C will be to the immediate right of F
• D. B will be to the immediate left of H
• A. B agrees to change her sitting position
• B. C agrees to change her sitting position
• C. G agrees to change her sitting position
• D. H agrees to change her sitting position
• A. A will be directly facing C
• B. B will be directly facing C
• C. A will be directly facing B
• D. B will be directly facing D
• A. C and B
• B. A and F
• C. D and C
• D. E and G

Answer 1

The Correct Option is C

Step 1: Use the loop A-C-E-G-B-D-F-H-A, where a clockwise (forward) step gives a person's left neighbour and an anti-clockwise (backward) step gives their right neighbour.

Step 2: Check each statement: A's right is H (not E) since the loop reads ...F-H-A-C..., so "E to the right of A" already fails; C's right is A ("A to the right of C" holds); B's left is D ("D to the left of B" holds); D's left is F ("F to the left of D" holds).

Conclusion: The false statement is "E will be to the immediate right of A".

Answer 2

Another way to check these statements is to go back to the original seating clues directly, before even using the full loop, since some statements can be ruled out purely on adjacency grounds:

1. A will be to the immediate right of C: Clue (a) directly states that A sits beside C, confirming they are indeed neighbours. Combined with the established clockwise direction of the loop, A does sit on C's right side, so this statement holds.
2. D will be to the immediate left of B: Clue (h) directly states that B sits beside D, confirming their adjacency. Following the established clockwise direction, D does sit on B's left side, so this statement holds.
3. E will be to the immediate right of A: Checking the original clues that mention A directly, clue (a) pairs A with C, and clue (b) pairs A with H. Nowhere in the original clues is A ever paired with E, meaning A and E are not even neighbours at all, let alone in the specific right-hand position claimed here. This statement fails on adjacency alone.
4. F will be to the immediate left of D: Clue (f) directly states that D sits beside F, confirming their adjacency. Following the established clockwise direction, F does sit on D's left side, so this statement holds.

Checking the raw clues shows that A's only two named neighbours are C and H, never E, which is enough on its own to identify this as the false statement, without even needing to work out left or right.

Therefore, the correct answer is E will be to the immediate right of A.

Answer 3

Step 1: Loop: A-C-E-G-B-D-F-H-A; clockwise (forward) means left neighbour, anti-clockwise (backward) means right neighbour.

Step 2: D's left is F, not B; F's right is D, not C; H's left is A, not B, so three of the statements fail.

Step 3: A's right (backward from A) is H, matching the remaining statement exactly.

Conclusion: "H will be to the immediate right of A" is correct.

Answer 4

A faster way to check these four statements is to first filter them using only the raw original clues, before worrying about direction at all, since a statement claiming two people are neighbours can be ruled out immediately if no clue ever pairs them:

1. B will be to the immediate left of D: Clue (h) does confirm B and D are neighbours, so this statement survives the adjacency filter and needs a direction check; following the established clockwise loop, D's left neighbour is actually F, not B, so this statement fails at the direction stage.
2. H will be to the immediate right of A: Clue (b) confirms H and A are neighbours, so this survives the adjacency filter. Following the clockwise loop, A's right neighbour is indeed H, so this statement passes both checks.
3. C will be to the immediate right of F: Checking the original clues that mention F, clue (d) pairs F with H, and clue (f) pairs F with D. C is never paired with F in any clue, so C and F are not even neighbours, and this statement is eliminated immediately.
4. B will be to the immediate left of H: Checking the original clues that mention H, clue (b) pairs H with A, and clue (d) pairs H with F. B is never paired with H in any clue, so this statement is also eliminated immediately on adjacency grounds.

Two statements fail immediately because the named pairs are never even neighbours, and of the two that do pass the adjacency check, only the direction for H and A works out correctly.

Therefore, the correct answer is H will be to the immediate right of A.

Answer 5

Step 1: On the loop A-C-E-G-B-D-F-H-A, find the shorter arc between A and F: going A to H to F uses only one person (H) in between; the other way around uses five people.

Step 2: B, C, and G all sit on the longer arc, far from the A-F gap, so moving any of them has no effect on whether A and F become neighbours.

Step 3: H is the single seat separating A and F on the short arc, so removing H from that seat is the only way to make A and F adjacent.

Conclusion: A and F become neighbours only if H changes position.

Answer 6

This can also be checked directly from the original clues, without ever building the full seating loop. Looking only at the clues that mention A, clue (a) pairs A with C, and clue (b) pairs A with H. Looking only at the clues that mention F, clue (d) pairs F with H, and clue (f) pairs F with D. Let's test each option by checking whether that person shows up in both of these short lists:

1. B: B does not appear in either A's clue-list, C and H, or F's clue-list, D and H, so B has no direct connection to either person and cannot be the bridge between them.
2. C: C appears only in A's clue-list, not in F's, so C sits next to A but has no direct link to F at all.
3. G: G does not appear in either list, so G is unconnected to both A and F directly.
4. H: H appears in both lists, in clue (b) for A and clue (d) for F, making H the one person directly linked to both A and F at once.

Since H is the only name that shows up in both A's and F's original beside-clues, H must be the person occupying the single seat between them, and only H moving away from that seat can let A and F become neighbours.

Therefore, the correct answer is H agrees to change her sitting position.

Answer 7

Step 1: With 8 seats evenly spaced around the table, the seat directly opposite any person is exactly 4 positions away, since \( 8 \div 2 = 4 \).

Step 2: Numbering the loop A-C-E-G-B-D-F-H as positions 0 to 7, A sits at position 0.

Step 3: Moving 4 positions from A lands on B, and checking the other direction also lands on B, confirming the pairing both ways.

Conclusion: A sits directly facing B.

Answer 8

A quicker filter is to check the original clues first, since anyone stated to be "beside" someone else cannot also be directly facing them, being adjacent and being opposite are mutually exclusive on a round table:

1. A will be directly facing C: Clue (a) directly states "A will sit beside C," meaning they are immediate neighbours. Since neighbours can never be directly opposite each other, this statement is false without needing any further counting.
2. B will be directly facing C: No clue pairs B and C as neighbours, so this survives the adjacency filter, but counting around the loop from C to B passes only two people, not the three required for a true opposite pair on an eight-seat table, so this statement is false.
3. A will be directly facing B: No clue pairs A and B as neighbours, so this survives the filter, and counting around the loop from A to B in either direction passes exactly three people each way, confirming a genuine opposite pair.
4. B will be directly facing D: Clue (h) directly states "B will sit beside D," meaning they are immediate neighbours, so they cannot be directly opposite, and this statement is eliminated immediately without any counting.

Two of the four options are eliminated instantly by the original clues alone, since neighbours can never be opposite, and of the remaining two, only A and B satisfy the three-person gap required for a true opposite pair.

Therefore, the correct answer is A will be directly facing B.

Answer 9

Step 1: Scan the original clues for any statement naming H: clue (b) "H will sit beside A" and clue (d) "F will sit beside H".

Step 2: A round table gives every person exactly two neighbours, and these two clues already supply both of them for H, so no other clue is needed.

Step 3: No other option pairing (C and B, D and C, E and G) appears anywhere alongside H in the original clues.

Conclusion: H sits between A and F.

Answer 10

Another way to confirm this is to build out a complete neighbour list for all eight people at once, as a byproduct of solving the whole seating arrangement, and then simply look up H's entry in that list: A pairs with C and H; C pairs with A and E; E pairs with C and G; G pairs with E and B; B pairs with G and D; D pairs with B and F; F pairs with D and H; H pairs with F and A. Let's check each option against this full list:

1. C and B: Looking up H's entry in the list gives F and A as its neighbours, not C and B, so this option does not match.
2. A and F: H's entry in the list reads exactly "F and A," matching this option precisely.
3. D and C: H's confirmed neighbours are F and A, not D and C, so this option is incorrect.
4. E and G: H's confirmed neighbours are F and A, not E and G, so this option is also incorrect.

The complete neighbour list built from all eight clues confirms that H's row reads "F and A," and no other pairing matches this entry.

Therefore, the correct answer is A and F.