Question

Reaction of \(BeCl_2\) with \(LiAlH_4\) gives :

1. \(AlCl_3\)
2. \(BeH_2\)
3. \(LiH\)
4. \(LiCl\)
5. \(BeAlH_4\)

Choose the correct answer from the options given below :

• A. (A), (D) and (E)
• B. (A), (B) and (D)
• C. (D) and (E)
• D. (B), (C) and (D)

Answer 1

The Correct Option is B

To solve this question, we need to understand the chemical reaction between beryllium chloride (\( BeCl_2 \)) and lithium aluminum hydride (\( LiAlH_4 \)). When these two compounds react, the products are typically the result of the reduction of beryllium chloride by lithium aluminum hydride.

The balanced chemical reaction for this process is:

\( 2BeCl_2 + LiAlH_4 \rightarrow 2BeH_2 + AlCl_3 + LiCl \)

In this reaction:

• \( BeH_2 \) is produced by the reduction of \( BeCl_2 \).
• \( AlCl_3 \) forms as a by-product from the interaction of \( Cl^{-} \) ions from \( BeCl_2 \) and aluminum.
• \( LiCl \) is formed from the lithium ion (from \( LiAlH_4 \)) and the chloride ion (from \( BeCl_2 \)).

Now, let's analyze each of the given options to identify the correct set of products:

1. \( AlCl_3 \): This is a correct product of the reaction.
2. \( BeH_2 \): This is another correct product of the reaction due to the reduction of \( BeCl_2 \).
3. \( LiH \): This is not produced in this reaction.
4. \( LiCl \): This is correctly produced in the reaction, as explained.
5. \( BeAlH_4 \): This compound is not formed in the reaction.

Based on the analysis, the correct answer is (A), (B), and (D) because these represent the actual products formed during the reaction of \( BeCl_2 \) with \( LiAlH_4 \).