Question:medium
Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of electron in this orbit is E/x, then x = ______.
(Given a0 = 0.529Å, E = energy of electron in ground state)
Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of electron in this orbit is E/x, then x = ______.
(Given a0 = 0.529Å, E = energy of electron in ground state)
(Given a0 = 0.529Å, E = energy of electron in ground state)
Updated On: Jan 14, 2026
Show Solution
Correct Answer: 16
Solution and Explanation
Known information:
\[ r = 0.529 \frac{n^2}{Z} \implies 8.48 = 0.529 \frac{n^2}{1} \]
\[ n^2 = 16 \implies n = 4 \]
Additional known information:
\[ E \propto \frac{1}{n^2} \]
\[ E_n = \frac{E}{16} \]
Therefore, $x = 16$.
Was this answer helpful?
0
Top Questions on Atomic Structure
The wavelength of spectral line obtained in the spectrum of Li$^{2+}$ ion, when the transition takes place between two levels whose sum is 4 and difference is 2, is
- JEE Main - 2026
- Chemistry
- Atomic Structure
- Among the following, the CORRECT combinations are
A. \( \mathrm{IF_3} \rightarrow \) T-shaped (\( sp^3d \))
B. \( \mathrm{IF_5} \rightarrow \) Square pyramidal (\( sp^3d^2 \))
C. \( \mathrm{IF_7} \rightarrow \) Pentagonal bipyramidal (\( sp^3d^3 \))
D. \( \mathrm{ClO_4^-} \rightarrow \) Square planar (\( sp^2d \))
Choose the correct answer from the options given below:
- JEE Main - 2026
- Chemistry
- Atomic Structure
Spherical node shown in figure-1 is best represented by which point in figure-2.
- JEE Main - 2026
- Chemistry
- Atomic Structure
- The energy of first (lowest) Balmer line of H atom is \(x\) J. The energy (in J) of second Balmer line of H atom is:
- JEE Main - 2026
- Chemistry
- Atomic Structure
- Want to practice more? Try solving extra ecology questions todayView All Questions
