To ascertain the reaction products of an ether with hydrogen iodide (HI), we examine the C-O bond cleavage mechanism.
- The ether in question is cyclic, with an isopropyl group attached to the oxygen.
- Upon addition of HI, the iodide ion (I-) attacks the more sterically hindered carbon of the ether, yielding an alcohol and an alkyl iodide.
- The tertiary butyl group represents the more hindered side in this reaction. Iodide ion attack at this position cleaves the C-O bond.
- This cleavage results in the formation of isopropanol and tertiary butyl iodide.
Consequently, the reaction products are isopropanol and tertiary butyl iodide.
The correct answer is the image depicting isopropanol and tertiary butyl iodide.