To save time, check the signs of \(x\) and \(y\) first:
\(x = -4\) (negative) and \(y = 4\sqrt{3}\) (positive) puts the point in the second quadrant.
The only second-quadrant angle among the choices is \(\frac{2\pi}{3}\) (since \(\frac{\pi}{3}\) and \(\frac{\pi}{6}\) are in Quadrant I, and \(\frac{5\pi}{6}\) would require different coordinates).
This immediately points to Option (C).