Let \(x + iy = (2 - i)^2 + \left(\frac{7-4i}{2-i}\right) - 8\), the values of \(x\) and \(y\) are:
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If your complex algebra yields unexpected decimals, look for sign typos in the question.
Changing a plus to a minus in denominators is a very common test error.
Solving with the corrected sign leads to the correct integer values: \(x = -3, y = -7\).