Question:medium

Pinky is standing in a queue at a ticket counter. Suppose the ratio of the number of persons standing ahead of Pinky to the number of persons standing behind her in the queue is 3:5. If the total number of persons in the queue is less than 300, then the maximum possible number of persons standing ahead of Pinky is

Updated On: Jan 15, 2026
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Solution and Explanation

1. Variable Representation

Let:

  • Number of persons ahead of Pinky = \( 3x \)
  • Number of persons behind Pinky = \( 5x \)
  • \( x \) is a positive integer

The ratio of persons ahead to behind is:

\[ \frac{3x}{5x} = \frac{3}{5} \]

2. Total Persons in the Queue

Total persons = Persons ahead + Pinky + Persons behind

\[ 3x + 1 + 5x = 8x + 1 \]

Given: Total persons<300

\[ 8x + 1<300 \]

Subtract 1 from both sides:

\[ 8x<299 \]

Divide by 8:

\[ x<\frac{299}{8} \Rightarrow x<37.375 \]

The maximum possible integer value for \( x \) is 37.

3. Calculate Maximum Number of Persons Ahead of Pinky

Maximum number ahead = \( 3x \)

\[ \text{Maximum } 3x = 3 \times 37 = 111 \]

The maximum number of persons standing ahead of Pinky is 111.

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