Let:
The ratio of persons ahead to behind is:
\[ \frac{3x}{5x} = \frac{3}{5} \]
Total persons = Persons ahead + Pinky + Persons behind
\[ 3x + 1 + 5x = 8x + 1 \]
Given: Total persons<300
\[ 8x + 1<300 \]
Subtract 1 from both sides:
\[ 8x<299 \]
Divide by 8:
\[ x<\frac{299}{8} \Rightarrow x<37.375 \]
The maximum possible integer value for \( x \) is 37.
Maximum number ahead = \( 3x \)
\[ \text{Maximum } 3x = 3 \times 37 = 111 \]
The maximum number of persons standing ahead of Pinky is 111.