Given a total of \(100x\) employees, with each earning \(100y\), we proceed with the analysis.
This department comprises 20% of the total employees, equating to \(20x\) individuals. Their collective salary is one-sixth of the organization's total payroll.
Total salary for the manufacturing department:
\(\frac{1}{6} \times 100x \times 100y = \frac{10000xy}{6}\)
Average salary in the manufacturing department:
\(\frac{\frac{10000xy}{6}}{20x} = \frac{500y}{6x}\)
The non-manufacturing department accounts for the remaining 80% of the workforce, comprising \(80x\) employees. Their combined salary is:
\(\frac{50000xy}{6}\)
Average salary in the non-manufacturing department:
\(\frac{\frac{50000xy}{6}}{80x} = \frac{500y}{24x}\)
The ratio of the average salary in the manufacturing department to that in the non-manufacturing department is calculated as follows:
\(\frac{\frac{500y}{6x}}{\frac{500y}{24x}} = \frac{500y}{6x} \times \frac{24x}{500y} = \frac{24}{6} = 4:15\)
The ratio of the average salary in the manufacturing department to the average salary in the non-manufacturing department is determined to be 4:15.
Therefore, the correct option is (B): 4:15.