For very dilute strong acids, account for the autoionization of water when calculating pH.
The HCl solution has a concentration of \(10^{-8}\) M. As HCl is a strong acid, its contribution to [H+] is \(10^{-8}\) M. Water autoionization also produces [H+] = \(10^{-7}\) M. The total [H+] is:
\( \text{Total} [\text{H}^+] = 10^{-8} + 10^{-7} \approx 1.1 \times 10^{-7} \text{ M} \)
The pH is calculated as follows:
\( \text{pH} = -\log[\text{H}^+] \approx -\log(1.1 \times 10^{-7}) \approx 6.96 \)
Therefore, the pH falls between 6 and 7.