Question:medium

$(p \land q) \lor (\sim p \land \sim q)$ is

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$(p \land q) \lor (\sim p \land \sim q)$ is equivalent to $p \leftrightarrow q$.

Updated On: Apr 8, 2026

a contradiction
a tautology
either (a) or (b)
neither (a) nor (b)

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The Correct Option is D

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If $f(x) = \begin{cases} x, & 0 \le x \le 1 \\ 2x - 1, & 1<x \end{cases}$, then

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