Question:medium

Oxygen has an oxidation state of +2 in

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Oxygen usually exhibits -2 oxidation state. It shows positive oxidation states only when combined with fluorine, the most electronegative element.
Updated On: May 2, 2026
  • \(H_2O_2\)
  • \(H_2O\)
  • \(F_2O\)
  • \(SO_2\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Basic Principle
Oxidation state is determined by electronegativity differences. Fluorine is the most electronegative element.
Step 2: Solution Procedure:

(A) \(H_2O_2\): Let O.N. of O be x. \(2(+1) + 2x = 0 \Rightarrow 2 + 2x = 0 \Rightarrow x = -1\).
(B) \(H_2O\): \(2(+1) + x = 0 \Rightarrow x = -2\).
(C) \(F_2O\): F has O.N. -1. \(2(-1) + x = 0 \Rightarrow -2 + x = 0 \Rightarrow x = +2\).
(D) \(SO_2\): Let O.N. of O be x. S has O.N. +4. \(4 + 2x = 0 \Rightarrow 2x = -4 \Rightarrow x = -2\).

Step 3: Required Answer:
Oxygen has +2 oxidation state in \(F_2O\), option (C).
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