Organic compound (X) + KOH \( \overset{H^+}{\rightarrow} \) gives product \( P \) having the same molar ratio of C : H : O. Identify product \( P \).
Show Hint
In reactions involving KOH and organic compounds, pay attention to the formation of products like alcohols, carboxylic acids, or aldehydes, which can show different molar ratios.
Step 1: Identifying the reaction.
The organic compound \( X \) reacts with KOH in the presence of \( H^+ \) to give a product \( P \) that has the same molar ratio of C : H : O.
Step 2: Interpreting the given information.
- The presence of hydroxyl group \( \text{OH} \) and the molar ratio of C : H : O suggests that the compound is likely to be an alcohol or acid.
- The product \( P \) is consistent with the structure of acetic acid \( \text{CH}_3 \text{COOH} \) or an aldehyde/ketone.
- Among the options, option (A) \( \text{CH}_2 \text{C} \text{OH} \) shows a possible reaction forming a compound with same molar ratio.
Step 3: Conclusion.
From the given molar ratio and product formation, we conclude that the correct answer is option (A).
Final Answer: (A) \( \text{CH}_2 \text{C} \text{OH} \)
