On the specified surface, if \(35 \%\) of incident radiation energy is reflected and the transmissivity of the body is \(0.3\), then the emissivity of the surface is
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Radiation properties summary for any material surface:
- $\alpha + \rho + \tau = 1$
- For an opaque body, transmissivity is zero ($\tau = 0 \implies \alpha + \rho = 1$).
- By Kirchhoff's Law, always equate Emissivity directly to Absorptivity ($\epsilon = \alpha$) under thermal equilibrium conditions.