Question

On average, how many fragments would a restriction enzyme, which recognizes a specific 5-base sequence in DNA, be expected to cleave a double-stranded bacteriophage with a genome size of 6066 bp into?

• A. About 1212
• B. About 120
• C. About 60
• D. About 6

Hint:

A 4-base cutter cuts every \(4^4 = 256\) bp, a 5-base cutter cuts every \(4^5 = 1024\) bp, and a 6-base cutter cuts every \(4^6 = 4096\) bp.
Dividing 6066 bp by 1024 bp gives approximately 6, which quickly points to the correct answer.

Answer 1

The Correct Option is D