Question:medium

Observe the given cell \[ Cr|Cr^{3+}(0.1M)||Fe^{2+}(0.01M)|Fe \] What is the cell potential (in V) for the above cell? Given: \[ E^\circ_{Cr^{3+}/Cr}=-0.74V \] \[ E^\circ_{Fe^{2+}/Fe}=-0.44V \] \[ \frac{2.303RT}{F}=0.06V \]

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Always determine: \[ E^\circ_{cell} = E^\circ_{cathode} - E^\circ_{anode} \] before applying the Nernst equation.
Updated On: Jun 22, 2026
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The Correct Option is A

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