Question

Observe the following statements
Statement-I: Hybridisation is not same in both SF₆ and BrF₅.
Statement-II: BrF₅ is Square pyramidal while SF₆ is octahedral in shape
The correct answer is

• A. Both statements I and II are correct
• B. Statement I is correct, but statement II is not correct
• C. Statement I is not correct, but statement II is correct
• D. Both statements I and II are not correct

Hint:

To determine hybridization and shape: 1. Find the central atom. 2. Count its valence electrons. 3. Add/subtract electrons for any charge. 4. Add one electron for each monovalent atom bonded (like H, F, Cl). 5. Divide the total by 2 to get the number of electron pairs (Steric Number). 6. Determine hybridization from the steric number (2=\(sp\), 3=\(sp^2\), 4=\(sp^3\), 5=\(sp^3d\), 6=\(sp^3d^2\)). 7. Determine the shape based on the number of bond pairs and lone pairs.

Answer 1

The Correct Option is A

Step 1: Analyze \( SF_6 \): S (Group 16) has 6 valence e-. 6 bonds with F. 0 lone pairs. Steric Number = 6. Hybridisation = \( sp^3d^2 \). Shape = Octahedral.
Step 2: Analyze \( BrF_5 \): Br (Group 17) has 7 valence e-. 5 bonds with F. 1 lone pair. Steric Number = 5 + 1 = 6. Hybridisation = \( sp^3d^2 \). Shape = Square Pyramidal.
Step 3: Evaluate Statements: - Statement I: Claims hybridisation is "not same". Since both are \( sp^3d^2 \), this is Incorrect. - Statement II: Correctly identifies shapes (Octahedral vs Square Pyramidal). This is Correct.