Observe the following set of reactions
What are $\text{X}, \text{Y}$ and $\text{Z}$ respectively?
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The Rosenmund reduction ($\text{H}_2/\text{Pd}-\text{BaSO}_4$) is a name reaction for the partial reduction of acyl chlorides to aldehydes. Organometallic reagents like $\text{R}_2\text{Cd}$ are best for ketone synthesis. Aldol condensation of aromatic aldehydes with base (like $\text{C}_6\text{H}_5\text{CHO}$) is typically a Cannizzaro reaction, unless a strong nucleophile is added.
$\text{H}_2/\text{Pd}; (\text{CH}_3)_2\text{Cd}; \text{C}_6\text{H}_5\text{CH}=\text{CH}-\text{C}_6\text{H}_5$ (This is wrong $\text{C}_6\text{H}_5\text{CH}=\text{CH}-\text{C}_6\text{H}_5$ is stilbene)
To determine the correct reagents and products in the given reaction sequence, let's analyze each step involved:
Initial Reaction with Reagent X:
The starting compound is \(\text{C}_6\text{H}_5\text{COCl}\) (Benzoyl chloride). Reaction with reagent \(\text{X}\) transforms it into \(\text{C}_6\text{H}_5\text{CHO}\) (Benzaldehyde).
This conversion indicates the use of a reduction reagent. The most suitable reagent for this transformation is Rosenmund's catalyst, \(\text{H}_2/\text{Pd}-\text{BaSO}_4\).
Initial Reaction with Reagent Y:
Here, \(\text{C}_6\text{H}_5\text{COCl}\) is transformed into \(\text{C}_6\text{H}_5\text{COCH}_3\) (Acetophenone).
This transformation is characteristic of the reaction with a Grignard reagent, which provides a methyl group from \(\text{CH}_3\text{MgBr}\).
Subsequent Reaction to Form Z:
Both products undergo further reaction with \(\text{OH}^-\text{(aq)}\) at 293 K leading to the formation of a major product, \(\text{C}_6\text{H}_5\text{CH}=\text{CH}-\text{C}_6\text{H}_5\) (Stilbene).
This generally involves the Aldol condensation or similar mechanism leading to a double bond formation between carbon centers of two reactants.
Thus, the correct sequence of reagents and the expected products are:
