Question

Number of molecules having bond order 2 from the following molecule is ...................
$C_2, O_2, Be_2, Li_2, Ne_2, N_2, He_2$

Answer 1

Correct Answer: 2

To identify molecules with a bond order of 2, we first calculate the bond order for each molecule using the formula:

Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2

Applying this formula to each molecule:

$C_2$	Bond Order = (6 bonding electrons - 2 antibonding electrons) / 2 = 2
$O_2$	Bond Order = (8 bonding electrons - 4 antibonding electrons) / 2 = 2
$Be_2$	Bond Order = (2 bonding electrons - 2 antibonding electrons) / 2 = 0
$Li_2$	Bond Order = (2 bonding electrons - 0 antibonding electrons) / 2 = 1
$Ne_2$	Bond Order = (8 bonding electrons - 8 antibonding electrons) / 2 = 0
$N_2$	Bond Order = (10 bonding electrons - 4 antibonding electrons) / 2 = 3
$He_2$	Bond Order = (2 bonding electrons - 2 antibonding electrons) / 2 = 0

Upon review, $C_2$ and $O_2$ both exhibit a bond order of 2. Therefore, there are 2 molecules with this bond order.

This result falls within the expected range of 2 to 2, confirming the accuracy of the calculation.