To establish the correspondence between tetrahedral complexes in List-I and their electronic configurations in List-II, we must examine the oxidation states and electron configurations of the metal ions:
- Titanium Tetrachloride, TiCl4:
- Titanium exhibits a +4 oxidation state in TiCl4, yielding a d0 electron configuration.
- Electronic configuration: e0, t20. (Configuration III represents the d0 state where unpaired electrons are initially assigned to the e orbitals).
- Ferrate Ion, [FeO4]2-:
- Iron in [FeO4]2- is typically in the +6 oxidation state, leading to the complete removal of 3d electrons and a vacant orbital.
- Electronic configuration: e0, t20. (Configuration I aligns with vacant t2 orbitals, with e orbitals being filled).
- Tetrachloroferrate(III), [FeCl4]-:
- In [FeCl4]-, iron is in the +3 oxidation state, resulting in a d5 electronic configuration.
- Electronic configuration: e2, t23. (Configuration IV corresponds to a high spin d5 configuration).
- Tetrachlorocobaltate(II), [CoCl4]2-:
- Cobalt in the +2 oxidation state within this complex possesses a d7 configuration.
- Electronic configuration: e4, t23. (Configuration II matches a high spin d7 configuration, differentiating between paired and unpaired electrons).
Accordingly, the correct pairings of List-I with List-II are:
- (A) TiCl4 - (III) e0, t20
- (B) [FeO4]2- - (I) e0, t20
- (C) [FeCl4]- - (IV) e2, t23
- (D) [CoCl4]2- - (II) e4, t23
Therefore, the definitive answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II)