Question

Match List I with List II

List-I	Reaction	List-II	Reagents
(A)	Hoffmann Degradation	(I)	Conc.KOH,\(\triangle\)
(B)	Clemenson reduction	(II)	CHCl3, NaOH/H3O+
(C)	Cannizaro reaction	(III)	Br2, NaOH
(D)	Reimer-Tiemann Reaction	(IV)	Zn-Hg/HCl

Choose the correct answer from the option given below:

• A. (A)-III, (B) -IV, (C) – II, (D)-I
• B. (A)-III, (B) -IV, (C) –I, (D)-II
• C. (A)-II, (B) -IV, (C) –I, (D)-III
• D. (A)-II, (B) -I, (C) – III, (D)-IV

Hint:

For reaction and reagent matching:
• Focus on identifying the reagents specific to each reaction’s mechanism.
• Recall key reagents used for reductions, substitutions, or rearrangements in named reactions.

Answer 1

The Correct Option is B

 To solve the given problem, we need to match the chemical reactions listed in List-I with their corresponding reagents from List-II.

1. Hoffmann Degradation: This reaction involves the conversion of an amide to an amine with one carbon less than the original amide. The reagent used is Br₂ with NaOH. Hence, the correct match is (A) - III.
2. Clemenson Reduction: This is a reduction reaction that converts a carbonyl group (ketone or aldehyde) into a methylene group using Zn-Hg and HCl as reagents. Thus, (B) - IV is the correct match.
3. Cannizaro Reaction: This involves the disproportionation of an aldehyde without a hydrogen atom on the alpha carbon in the presence of a strong base. The typical reagent is Conc.KOH. Therefore, the correct match is (C) - I.
4. Reimer-Tiemann Reaction: This reaction is used to form ortho-formyl derivatives of phenols using the reagents CHCl₃, NaOH/H₃O⁺. Consequently, (D) - II is the correct match.

Thus, the correct matching sequence is:

(A) - III, (B) - IV, (C) - I, (D) - II

This matches the given correct answer:

(A)-III, (B) -IV, (C) –I, (D)-II