Question

Match List-I with List -II

List - I	List - II
(A) \(ψ_{MO}=ψ_A-ψ_B\)	(I) Dipole moment
(B) \(µ=Q×r \)	(II) Bonding molecular orbital
(C) \(\frac{N_b-N_a}2\)	(III) Anti-bonding molecular orbital
(D) \(ψ_{MO}=ψ_A+ψ_B\)	(IV) Bond order

Choose the correct answer from options given below:

• A. A(II), B(I), C(IV), D(III)
• B. A(III), B(IV), C(I), D(II)
• C. A(III), B(I), C(IV), D(II)
• D. A(III), B(IV), C(II), D(I)

Answer 1

The Correct Option is C

This question requires matching entries from List-I with entries from List-II based on the characteristics of molecular orbitals, dipole moment, and bond order. Let's go step-by-step to find the correct matches:

1. Match (A) \(ψ_{MO}=ψ_A-ψ_B\):

   This expression represents an anti-bonding molecular orbital (ABMO). In quantum chemistry, the wave function of an anti-bonding molecular orbital is the difference between the atomic wave functions, \(ψ_A\) for atom A and \(ψ_B\) for atom B. Hence, (A) corresponds to (III) Anti-bonding molecular orbital.

2. Match (B) \(µ=Q×r\):

   This formula represents the dipole moment, where \(µ\) is the dipole moment, \(Q\) is the charge, and \(r\) is the distance between the charges. Therefore, (B) corresponds to (I) Dipole moment.

3. Match (C) \(\frac{N_b-N_a}2\):

   This expression is used to calculate bond order, where \(N_b\) is the number of electrons in bonding orbitals and \(N_a\) is the number of electrons in anti-bonding orbitals. Therefore, (C) corresponds to (IV) Bond order.

4. Match (D) \(ψ_{MO}=ψ_A+ψ_B\):

   This expression represents a bonding molecular orbital (BMO), wherein the wave function is the sum of atomic wave functions, indicating constructive interference. Therefore, (D) corresponds to (II) Bonding molecular orbital.

The correct matching is:

• A(III)
• B(I)
• C(IV)
• D(II)

Thus, the correct answer is:
A(III), B(I), C(IV), D(II)