Question

Match List-I with List-II.

	(Si-Compounds)		(Si-Polymeric/other Products)
A.	\((CH_3)_4Si\)	i	Chain Silicone
B.	\((CH_3)Si(OH)_3\)	ii	Dimeric Silicone
C.	\((CH_3)_2Si(OH)_2\)	iii	Silane
D.	\((CH_3)_3Si(OH)\)	iv	2D-Silicone

Choose the correct answer from the options given below:

• A. (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
• B. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
• C. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
• D. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Answer 1

The Correct Option is D

To solve this question, we need to match the given silicon compounds with their corresponding polymeric forms or other silicon-based products. Let's break down the components:

1. Compound: \((CH_3)_4Si\)
   This compound is known as Tetramethylsilane, which belongs to the family of silanes. Silanes are compounds that consist of silicon bonded to hydrogen and/or organic groups. Thus, this matches with iii. Silane.
2. Compound: \((CH_3)Si(OH)_3\)
   This compound can form a network or 2D structure due to its three hydroxyl groups, which can participate in condensation reactions, leading to cross-linking. Therefore, it forms a 2D-Silicone. Thus, this matches with iv. 2D-Silicone.
3. Compound: \((CH_3)_2Si(OH)_2\)
   This is a basic unit capable of forming long chain structures through condensation reactions. Hence, it is known for forming a Chain Silicone. So, this pairs with i. Chain Silicone.
4. Compound: \((CH_3)_3Si(OH)\)
   This compound with one hydroxyl group can create dimers, as it can link with similar molecules. It matches with ii. Dimeric Silicone.

Based on the above explanations, the correct match is:

1. (A) \((CH_3)_4Si\) - (iii) Silane
2. (B) \((CH_3)Si(OH)_3\) - (iv) 2D-Silicone
3. (C) \((CH_3)_2Si(OH)_2\) - (i) Chain Silicone
4. (D) \((CH_3)_3Si(OH)\) - (ii) Dimeric Silicone

Thus, the correct option is:

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)