Question

Match List I with List II:

List I		List II
A	16 g of CH4 (g)	I	Weight 28g
B	1 g of H2 (g)	II	60.2 × 1023 electrons
C	1 mole of N2 (g)	III	Weighs 32 g
D	0.5 mol of SO2 (g)	IV	Occupies 11.4 L volume at STP

Choose the correct answer from the options given below:

• A. A-II, B-IV, C-III, D-I
• B. A-I, B-III, C-II, D-IV
• C. A-II, B-IV, C-I, D-III
• D. A-II, B-III, C-IV, D-I

Answer 1

The Correct Option is C

To solve this problem, let's analyze each item in both lists and match them correctly:

1. **16 g of CH₄ (g):**
   • The molar mass of CH₄ (Methane) is 16 g/mol. Thus, 16 g of CH₄ is equivalent to 1 mole of CH₄, which contains Avogadro's number of molecules, each comprising 5 atoms (1 C and 4 H), leading to a total electron count of 60.2 × 10²³ electrons.
   • Match: II
2. **1 g of H₂ (g):**
   • The molar mass of H₂ is 2 g/mol. Therefore, 1 g of H₂ corresponds to 0.5 mole. At Standard Temperature and Pressure (STP), 1 mole of any gas occupies 22.4 L. Accordingly, 0.5 mole of H₂ occupies 11.2 L.
   • Match: IV
3. **1 mole of N₂ (g):**
   • The molar mass of N₂ is 28 g/mol, so 1 mole of N₂ weighs 28 g.
   • Match: I
4. **0.5 mol of SO₂ (g):**
   • The molar mass of SO₂ is 64 g/mol. Hence, 0.5 mole of SO₂ weighs 32 g.
   • Match: III

Based on these calculations and matches, the correct answer is:

A-II, B-IV, C-I, D-III