Question:medium

Match List I with List II:
List I - (Monomer)List II - (Polymer)
(A) Tetrafluoroethene(I) Orlon
(B) Acrylonitrile(II) Natural rubber
(C) Caprolactam(III) Teflon
(D) Isoprene(IV) Nylon-6

Choose the correct answer from the options given below:

Show Hint

Polymers are classified based on their monomer units and polymerization mechanism.

Updated On: Feb 25, 2026
  • (A)-(IIΙ), (B)-(Ι), (C)-(IV), (D)-(II)
  • (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  • (А)-(II), (Β)-(IIΙ), (C)-(IV), (D)-(I)
  • (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
Show Solution

The Correct Option is A

Solution and Explanation

To solve this matching problem, we need to identify the polymers formed from each of the given monomers based on the options provided and our knowledge of polymer chemistry.

  1. Tetrafluoroethene: This monomer forms Teflon upon polymerization. Teflon is the commercial name for polytetrafluoroethylene (PTFE). Therefore, the correct match is (A)-(III).
  2. Acrylonitrile: This monomer polymerizes to form Orlon. Orlon is a trade name for polyacrylonitrile, which is used in making fabrics. Therefore, the correct match is (B)-(I).
  3. Caprolactam: This monomer is used to produce Nylon-6. It undergoes ring-opening polymerization to form this polymer, which is widely used in textiles. Therefore, the correct match is (C)-(IV).
  4. Isoprene: This compound is the monomer of Natural rubber. It undergoes polymerization to form polyisoprene, which is the primary constituent of natural rubber. Therefore, the correct match is (D)-(II).

Based on the above analysis, the correct matching of List I with List II is:

  • (A) Tetrafluoroethene - (III) Teflon
  • (B) Acrylonitrile - (I) Orlon
  • (C) Caprolactam - (IV) Nylon-6
  • (D) Isoprene - (II) Natural rubber

Therefore, the correct answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II).

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