Question:medium

Match List-I with List-II
 List-I
(Complex)
 List-II
(Hybridization)
A.Ni(CO)4I.sp3
B.[Ni(CN)4]2-II.sp3d2
C.[Co(CN)6]3-III.d2sp3
D.[CoF6]3-IV.dsp2
Choose the correct answer from the options given below:

Updated On: Apr 19, 2026
  • A-IV, B-I, C-III, D-II
  • A-I. B-IV, C-III, D-II
  • A-I. B-IV, C-II, D-III
  • A-IV, B-I, C-II. D-III
Show Solution

The Correct Option is B

Solution and Explanation

To solve the given question, we need to determine the correct hybridization for each complex in List-I and match it with List-II. Let's analyze each complex:

  1. Ni(CO)4:
    • NICKEL (Ni) is in the zero oxidation state in \text{Ni(CO)}_{4}.
    • The electronic configuration of Ni is [Ar]3d^{8}4s^{2}.
    • CO is a strong field ligand, causing the pairing of electrons.
    • After electron pairing: 3d^{10}, and the 4s and three 4p orbitals hybridize to form sp^{3} hybridization.
    Therefore, for Ni(CO)4, the hybridization is sp3. Thus, A matches with I.
  2. [Ni(CN)4]2-:
    • Ni is in the +2 oxidation state in [\text{Ni(CN)}_{4}]^{2-}.
    • The electronic configuration of Ni2+ is [Ar]3d^{8}.
    • CN- is a strong field ligand, causing the pairing of electrons.
    • Two 3d, one 4s and one 4p orbitals hybridize to form dsp^{2} hybridization.
    Hence, for [Ni(CN)4]2-, the hybridization is dsp2. Thus, B matches with IV.
  3. [Co(CN)6]3-:
    • Co is in the +3 oxidation state in [\text{Co(CN)}_{6}]^{3-}.
    • The electronic configuration of Co3+ is [Ar]3d^{6}.
    • CN- is a strong field ligand, causing the pairing of all 3d electrons.
    • Two 3d, one 4s and three 4p orbitals hybridize to form d^{2}sp^{3} hybridization.
    Therefore, for [Co(CN)6]3-, the hybridization is d2sp3. Thus, C matches with III.
  4. [CoF6]3-:
    • Co is in the +3 oxidation state in [\text{CoF}_{6}]^{3-}.
    • The electronic configuration of Co3+ is [Ar]3d^{6}.
    • F- is a weak field ligand and does not cause pairing of the electrons.
    • Five 3d, one 4s and two 4p orbitals hybridize to form sp^{3}d^{2} hybridization.
    Hence, for [CoF6]3-, the hybridization is sp3d2. Thus, D matches with II.

After analyzing all the complexes, the correct matching is A-I, B-IV, C-III, D-II.

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